# rahulv336699

## rahulv336699Vellore Institute of Technology - VIT

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rahulv336699Lv10

25 Nov

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rahulv336699Lv10

25 Nov

Answer: Step-by-step explanation: Average is the sum of all observations divid...

rahulv336699Lv10

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rahulv336699Lv10

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Answer: Step-by-step explanation: Given that,Point estimate = sample mean = = ...

rahulv336699Lv10

25 Nov

Answer: Step-by-step explanation: first o all calculating the mean and standar...

rahulv336699Lv10

24 Nov

Answer: Step-by-step explanation: The margin of error (ME) is . a) When , b) W...

rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

24 Nov

Answer: Step-by-step explanation: Given that, = 101.0 = 99.5 = 3.1 = 5.0 n1 = ...

Diet Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Regular H2 36 0.81202 lb 0.00742 lb 11 36 0.79887 lb 0.00442 lb Cix a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? V O A. Ho: My = H2 Hy: My

rahulv336699Lv10

24 Nov

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rahulv336699Lv10

24 Nov

Answer: Step-by-step explanation: Given that , mean = = 50 standard deviation ...

rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

24 Nov

Answer: Sample size = 11

rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

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Answer: Step-by-step explanation: Step 1 of 3 From the information, observe th...

rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

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Answer: Step-by-step explanation: A college professor states that this year's ...

rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

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rahulv336699Lv10

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Answer: Step-by-step explanation:Ho: p = 0.68H1: p is not equal to 0.68

rahulv336699Lv10

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Answer: Step-by-step explanation: Test Results

rahulv336699Lv10

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Answer: Step-by-step explanation: Note: There is no need of degrees of freedom...

rahulv336699Lv10

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rahulv336699Lv10

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Answer: Step-by-step explanation: Test statistic = -0.309

rahulv336699Lv10

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rahulv336699Lv10

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In a clinical trial, 18 out of 846 patients taking a prescription drug daily complained of flulike symptoms. Suppose that it is known that 1.8% of patients taking competing drugs complain of flulike symptoms. Is there sufficient evidence to conclude that more than 1.8% of this drug's users experience flulike symptoms as a side effect at the a = 0.01 level of significance? Because npo (1-P) = 15 > 10, the sample size is less than 5% of the population size, and the sample can be reasonably assumed to be random, the requirements for testing the hypothesis are satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? p > 0.018 Ho: p = 0.018 versus H : (Type integers or decimals. Do not round.) Find the test statistic, 20- 20 = (Round to two decimal places as needed.) Find the P-value. P-value = (Round to three decimal places as needed.) Choose the correct conclusion below. O A. Since P-value >a, do not reject the null hypothesis and conclude that there is not sufficient evidence that more than 1.8% of the users experience flulike symptoms. OB. Since P-value a, reject the null hypothesis and conclude that there is not sufficient evidence that more than 1.8% of the users experience flulike symptoms. OD. Since P-value

rahulv336699Lv10

24 Nov

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rahulv336699Lv10

24 Nov

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rahulv336699Lv10

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rahulv336699Lv10

24 Nov

Answer: Step-by-step explanation: According to the given probability table of ...

rahulv336699Lv10

24 Nov

Answer: Step-by-step explanation: (a) H0: = 0 Ha: 0 Values of d are given by: ...

rahulv336699Lv10

24 Nov

Answer: Step-by-step explanation: from above: sd =1.737 p value =0.009 d) for ...

rahulv336699Lv10

24 Nov

Answer: Step-by-step explanation: Here the sample mean exceeds the population ...